A Floyd Mayweather Shakur Stevenson $2 million dollar signing on fee offer for the 2016 US Olympian has been made we understand.

According to a trusted source in the US, we understand that the offer has been made by Mayweather to secure the talented Olympic silver medallist to join Mayweather’s promotional outfit based in Las Vegas, Nevada, USA.

The news comes to us just days after another Las Vegas based promoter, Top Rank, signed another 2016 Olympian in the form of Irishman Michael Conlan.

During the recent 2016 Olympics in Rio, Floyd Mayweather was pictured with and shot on camera praising Newark fighter Stevenson after one of his bouts, and speculation then began that Mayweather was looking to sign him.

Stevenson is being tipped as one of America’s next big boxing stars and during his amateur career to date, the 19 year old has been stellar in perpetuating this notion with some excellent achievements thus far.

Competing in the 56kg weight class as an amateur and standing at 5’8 in height, if Conlan’s decision to fight at featherweight is anything to go by in recent days, perhaps Stevenson will look to compete somewhere around super-bantamweight (122lbs) to 126lbs (featherweight) when starting off his professional boxing career.

Indeed, there could be a budding rivalry in the pro ranks between both Stevenson and Conlan to come – which could be an exciting one to keep an eye on:

Michael Conlan says him and @ShakurStevenson was like #PacquiaoMayweather in the amateurs… only this one will take longer to make you fear

— Kevin Byrne (@KevByrneBox) September 21, 2016

If the above offer has been accepted, Stevenson will join a growing fighting stable that includes the likes of J’Leon Love, Ashley Theophane, Andrew Tabiti, Badou Jack and more at Mayweather Promotions.

Mayweather recently spoke of how he believes fighters deserve more and appears to be taking more of a hands on role as a promoter himself, consistently refuting claims in recent times that he will return to the ring as an active fighter himself.